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R7986A Datenblatt(PDF) 20 Page - STMicroelectronics |
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R7986A Datenblatt(HTML) 20 Page - STMicroelectronics |
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20 / 37 page ![]() Application information R7986A 20/37 DocID026997 Rev 1 The transfer function on the LC filter is given by: Equation 19 where: Equation 20 Equation 21 As seen in Section 5.3 on page 12, two different kinds of network can compensate the loop. In the two following paragraphs, the guidelines to select the Type II and Type III compensation network are illustrated. 6.4.1 Type III compensation network The methodology to stabilize the loop consists of placing two zeros to compensate the effect of the LC double pole, therefore increasing phase margin; then to place one pole in the origin to minimize the DC error on regulated output voltage; finally, to place other poles far from the zero dB frequency. If the equivalent series resistance (ESR) of the output capacitor introduces a zero with a frequency higher than the desired bandwidth (that is: 2 ESR COUT < 1 / BW), the Type III compensation network is needed. Multi-layer ceramic capacitors (MLCC) have very low ESR (< 1 m ), with very high frequency zero, so a Type III network is adopted to compensate the loop. In Figure 10, the Type III compensation network is shown. This network introduces two zeros (fZ1, fZ2) and three poles (fP0, fP1, fP2). They are expressed as: Equation 22 Equation 23 GLC s 1 s 2 f zESR -------------------------- + 1 s 2 Qf LC ---------------------------- s 2 f LC ------------------- 2 ++ ------------------------------------------------------------------------- = fLC 1 2 LCOUT 1 ESR ROUT --------------- + ------------------------------------------------------------------------ = fzESR 1 2 ESR C OUT -------------------------------------------- = Q ROUT LCOUT ROUT ESR + LCOUT ROUT ESR + ------------------------------------------------------------------------------------------ ROUT VOUT IOUT -------------- = , = fZ1 1 2 C 3 R1 R3 + ------------------------------------------------ = fZ2 1 2 R 4 C4 ------------------------------ = fP0 0 = fP1 1 2 R 3 C3 ------------------------------ = fP2 1 2 R 4 C4 C5 C4 C5 + -------------------- -------------------------------------------- = |
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