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CLC446AMC Datenblatt(PDF) 9 Page - National Semiconductor (TI) |
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CLC446AMC Datenblatt(HTML) 9 Page - National Semiconductor (TI) |
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9 / 12 page ![]() 9 http://www.national.com high frequency performance, maintain low parasitic capacitance from the diodes D1 and D2 to ground, and from the input of the CLC522 to ground. Figure 11: Full-Wave Rectifier Elliptic Low-pass, Anti-aliasing Filter Elliptic filters are often used in anti-aliasing applications. If there is noise or undesired signals at frequencies above 1/2 the sampling rate of an A/D converter, then these signals are aliased down into the operating frequency range, degrading the signal of interest. To filter out these undesired signal components, place a low pass filter in front of the A/D converter. The Typical Application depicted on the front page is a 10MHz, third-order elliptic filter. It has a voltage- controlled, voltage source (VCVS) topology using a CLC446. To calculate the component values for this filter, do the following: 1. Select the filter approximation function for your application (see References [1-2]). For this design we chose: Filter type = Elliptic Filter order (n) = 3 Passband ripple = 0.18dB Mininimum stopband attenuation (Amin) = 37.44dB Cuttoff frequency = 10MHz (at 0.18dB attenuation) These choices produce the following results: -3dB frequency = 12.7MHz Stopband corner frequency = 29.3MHz 2. Find the pole and zero locations. Reference [1] gave the following for our filter: Pole 1: α = 0.38621 Pole 2: α o = 0.88668 Zero 1: β = 1.13897 Zero 2: ω∞ = 3.3505 3. Denormalize the frequency by multiplying by the cutoff frequency ( ω o) in radians/second. For our filter we have: Cutoff frequency: ω o = 2π(10MHz) = 62.832 x 106rad/s Pole 1: α' = ω oα = 24.266 x 10 6rad/s Pole 2: α o ' = ω oαo = 55.712 x 10 6rad/s Zero 1: β' = ω oβ = 21.052 x 10 6rad/s Zero 2: ω∞' = ωoω∞ = 71.564 x 106rad/s 4. Calculate these intermediate coefficients used in Reference [2]. For this design, a = 0.64226, b = 7.7612 and c = 75.556 x 106. 5. Set the following resistance and capacitance scaling factors: R = an arbitrary value C = an arbitrary value We chose C = 47pF and R = 1.00k Ω. 6. Calculate the capacitor, resistor and gain (K) values using these equations: For this design, the calculated values are: C1 = 47pF, C2 = 91pF, C3 = C4 = 23.5pF, C5 = 17.95pF, R1 = R2 = 202.1Ω, R3 = 101.1Ω, R4 = 3190Ω, R5 = 1000Ω and K = 4.928. 7. Select the feedback resistor (Rf) and gain- setting resistor (Rg) values to obtain a non- inverting voltage gain of Av = K. See the DC Gain (non-inverting) sub-section for details on selecting these values. + - CLC446 Vo + - 500 Ω CLC522 250 Ω 250 Ω 3 250 Ω D1 D2 Rg 162 Ω R1 50 Ω R2 50 Ω 3 4 5 6 2 Rf 800 Ω Ro 50 Ω 20 Ω 12 9 10 Vg Rin 50 Ω Vin 2 6 c' ' a 2' c b ' c 2 2 2 = () + () == ∞ αβ αω CC CC C 2 C Cb 1 4 R 1 cC b RR R 2 R 4b cC 1 b 4cC RR C 1 R' K2 2C C a 2b 2 Cb 1 cR aC 1 34 2 3 12 3 4 2 5 5 o 2 4 2 = == ≥ − () = == = − () + = = =+ − + ⋅ − α |
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