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Datenblatt-Suchmaschine für elektronische Bauteile |
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Datenblatt-Suchmaschine für elektronische Bauteile |
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ADL5567ACPZN-R7 Datenblatt(PDF) 16 Page - Analog Devices |
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ADL5567ACPZN-R7 Datenblatt(HTML) 16 Page - Analog Devices |
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16 / 23 page  ADL5567 Data Sheet Rev. A | Page 16 of 23 INPUT AND OUTPUT INTERFACING The ADL5567 can be configured as a differential input to differen- tial output driver, as shown in Figure 40. The 50 Ω resistors, R1 and R2, combined with the input balun, provide a 50 Ω input match for the 100 Ω input impedance. The input and output 0.1 µF capacitors isolate the VCCX/2 bias from the source and balanced load. The load equals 200 Ω to provide the expected ac perfor- mance (see the Specifications section). VS 0.1µF 0.1µF 1:1 BALUN AC 50Ω R1 R2 ½ ADL5567 ½ RL ½ RL 50 Ω 50Ω 0.1µF 0.1µF + – Figure 40. Differential Input to Differential Output Configuration The differential gain of the ADL5567 is dependent on the source impedance and load, as shown in Figure 41. The differential gain (AV) can be determined by RL RL AV + × = 10 50 500 (1) AC ½ ADL5567 ½ RS ½ RS 0.1µF 0.1µF 50Ω 50Ω 500Ω 500Ω 5Ω 5Ω RL 0.1µF 0.1µF + – Figure 41. Differential Input Loading Circuit Single-Ended Input to Differential Output The ADL5567 can also be configured in a single-ended input to differential output driver, as shown in Figure 42. In this configura- tion, the gain of the device is reduced due to the application of the signal to only one side of the amplifier. The input and output 0.1 µF capacitors isolate the VCCx/2 bias from the source and the balanced load. The single-ended circuit configuration can be accomplished in three steps (see Figure 42), assuming a 50 Ω RS source. First, calculate the input impedance (RIN) of the amplifier using the following formula: ( ) + × = RF RG RF RG RIN 2 – 1 (2) Thus, RIN = 91.7 Ω. The next step is to calculate the termination of Resistor R2 (see Figure 42). Because RS must be equal to the parallel equivalent resistance of R2 and RIN, IN IN R R2 R R2 RS + × = Thus, R2 = RIN × RS /(RIN − RS) (3) When RS = 50 Ω and RIN = 91.7 Ω, R2 = 109 Ω. The last step is to calculate the gain path rebalancing resistor, R1 (see Figure 42), using the following formula: R2 RS R2 RS R1 + × = Thus, R1 = 34.0 Ω. AC ½ ADL5567 ½ ½ RS RG 50Ω RG 50Ω RF 500Ω RF 500Ω 5Ω 5Ω RL 0.1µF 0.1µF RL R1 0.1µF 0.1µF R2 + – Figure 42. Single-Ended Input to Differential Output Configuration See the AN-0990 Application Note for more information on terminating single-ended inputs. The single-ended gain configuration of the ADL5567 is dependent on the source impedance and load, as shown in Figure 43. AC ½ ADL5567 ½ ½ RS RG 50Ω RG 50Ω RF 500Ω RF 500Ω 5Ω 5Ω RL 0.1µF 0.1µF RL R1 34.2Ω 0.1µF 0.1µF R2 109 Ω + – Figure 43. Single-Ended Input Loading Circuit Determine the single-ended gain (AV1) using the following two equations: IN IN MATCH R R2 R R2 R + × = (4) where RMATCH is the input resistance value that matches RS, calculated as follows: RL RL R RS R R2 RS R2 R2 RS R2 RS A MATCH S MATCH V1 + × + × + × + × + = 10 50 500 (5) |
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